Can I please have some help !

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago

The number of girls who work at Super shopper is 2 more than 3 times the number of boys. If 30 boys work at super shopper; how m

mote1985 [20]

I think its 92 but im not entirely sure. hope it helps though

4 0

3 years ago

Read 2 more answers

5x – (13 – x) >_9x – 7

ad-work [718]

Answer:

x<_2

Step-by-step explanation:

first off solve this like a regular equation the >_ dosent matter till later

so basically first multiply - by 13 and -x so you get -13 and x (multiplying two negatives = a positive)

so its 5x-13+x>_9x-7

add 5x and x to get 6x-13 on one side

then you get 6x-13>_9x-7 then subtract -9x from both sides

so its now -3x-13>_-7 add 13 so you get -3x>_6

then divide both sides by -3 (when you divide an equation with a >< or <_ >_ by a negative number that sign switches) so it will now be x<_2

that your final answer hope this helps :)

6 0

3 years ago

Quadrilateral ABCD is inscribed in the circle. Which sentence is true?

astra-53 [7]

Answer:

A) A and B are supplementary

Step-by-step explanation:

we know that

For any inscribed quadrilateral in the circle , opposite angles will be supplementary

so

In this problem

Angle A and Angle B are supplementary angles

$m\angle A+m\angle C=180^o$

Angle B and Angle D are supplementary angles

$m\angle B+m\angle D=180^o$

therefore

The sentences that are true

A) A and B are supplementary

3 0

3 years ago

Find the true measurements of the missing angle and show your work

Wittaler [7]

Answer:

Angle = 45

Step-by-step explanation:

It is half of a right angle also (x = 15) :)

8 0

2 years ago