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skelet666 [1.2K]
3 years ago
12

Prove that lim x->0 cos(1/x) does not exist.

Mathematics
1 answer:
Annette [7]3 years ago
5 0
The limit of the function cos(1/x)  as x approaches zero can be determined by substituting x with zero to the expression given. IN this case, 1/0 is equal to infinity. Using the rule of cosines, the maximum value of the cosine expression is 1. Hence the limit should be 1.
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Here is a balanced hanger diagram
suter [353]

Based on the mass of the circle and the triangle, we can find the mass of the square to be<u> 3.33 grams</u>

<h3>Mass of each side of hanger </h3>

Assuming the mass of the square is x, the equation for the first side is:

= (3 x mass of circle) + (2 x mass of triangle) + (6 x mass of square)

= ( 3 x 2) + ( 2 x 4) + ( 6 × x)

= 6 + 8 + 6x

Mass of other side:

=  (2 x mass of circle) + (5 x mass of triangle) + (3 x mass of square)

= ( 2 x 2) + ( 5 x 4) + ( 3 × x)

= 4 + 20 + 3x

<h3>Mass of square </h3>

As both sides are equal, equate both formulas to find x:

6 + 8 + 6x = 4 + 20 + 3x

6x - 3x = 24 - 14

3x = 10

x = 10/3

x = 3.33 grams

In conclusion, each square is 3.33 grams.

Find out more on problems requiring equating at brainly.com/question/20213883.

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