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LUCKY_DIMON [66]

2 years ago

8

10-x/3 + 12+6/9 when x= 4

1 answer:

Goshia [24]2 years ago

8 0

Answer:

5 i think mabe

Step-by-step explanation:

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I am thinking of two numbers.

taurus [48]

Answer:

6 and 8

Step-by-step explanation:

6+8=14 difference 2

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2 years ago

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Find the measure of each marked angle no

daser333 [38]

They equal to 180 because they are supplementary angles

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Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

2 years ago

What is the value of x?

artcher [175]

By Sine Rule,

x/sin30° = 8/sin90°

x/0.5 = 8/1

So x = 4.

8 0

3 years ago

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What is the area of this figure?<br><br> Enter your answer in the box.<br><br> mm²

Rainbow [258]

Answer:

$84mm^{2}$

I think this is true

7 0

2 years ago