Question

Find the distance between the points (2.7, 5.1) and (3, 4.7). 0.05 0.5 5

Answer 1

D = sqrt (x2 - x1)^2 + (y2 - y1)^2
(2.7,5.1)...x1 = 2.7 and y1 = 5.1
(3,4.7)...x2 = 3, and y2 = 4.7
now we sub
d = sqrt (3 - 27/10)^2 + (47/10 - 51/10)^2
d = sqrt (3/10^2) + (-2/5^2)
d = sqrt (9/100 + 4/25)
d = sqrt 1/4
d = 1/2 or 0.5 <==

Answer 2

Answer: 0.5 units.

Step-by-step explanation:

To find the distance between two points $(x_1,y_1)\ and (x_2,y_2)$ is given by distance formula :-

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Now, the distance between the points (2.7, 5.1) and (3, 4.7) is given by :-

$D=\sqrt{(3-2.7)^2+(4.7-5.1)}\\\\=\sqrt{(0.3)^2+(-0.4)^2}\\\\=\sqrt{0.09+0.16}\\=\sqrt{0.25}=0.5$

Hence, the distance between the points (2.7, 5.1) and (3, 4.7) is 0.5 units.