Answer:
t = 1/2n-6, nER
Step-by-step explanation:
Answer:
When there are 108 presents, there are 60 candy canes
Step-by-step explanation:
candy canes : presents = 5:9
5/9 = x/108
cross multiply:
(5) (108) = 9x
540 = 9x, divide both sides by 9
x = 60
Answer:
Step-by-step explanation:
Given:
Type of Flowers = 5
To choose = 4
Required
Number of ways 4 can be chosen
The first flower can be chosen in 5 ways
The second flower can be chosen in 4 ways
The third flower can be chosen in 3 ways
The fourth flower can be chosen in 2 ways
Total Number of Selection = 5 * 4 * 3 * 2
Total Number of Selection = 120 ways;
Alternatively, this can be solved using concept of Permutation;
Given that 4 flowers to be chosen from 5,
then n = 5 and r = 4
Such that

Substitute 5 for n and 4 for r





Hence, the number of ways the florist can chose 4 flowers from 5 is 120 ways
In radical form, the shortest distance from ( -4 , 4 ) and the line y = -2x + 6 is
2√5 units.
Attached below is the calculation to arrive at the answer as well as a graph.
X=2h, y=3k
Substitute these values into equations.
y+2x = 4 ------> 3k+2*2h=4 -----> 3k +4h =4
2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1
We have a system of equations now.
3k +4h =4 ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1
2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0
4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0
(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0
Denominator cannot be = 0
4h(2-2h)≠0
Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4 or h=-1
Check which
4h(2-2h)≠0
1) h= 3/4 , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.
h=3/4, then 3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then 3k = 4-4*(-1) =8 , 3k=8, k=8/3
So,
if h=3/4, then k=1/3,
and if h=-1, then k=8/3 .