Solve each equation with (0, 3)
y = -x + 3
3 = -0 + 3
y = 3 (correct since y = 3 in (0, 3))
y = 2x - 3
3 = 2(0) - 3
3 = 0 - 3
3 = -3 (incorrect since it isn't equal)
So... No, because it does not check in the second equation.
Best of Luck!
Answer:
Step-by-step explanation:
A line perpendicular to the y-axis, which is vertical, is a line that is horizontal. Perfectly horizontal lines always have a slope of 0. Thus, the equation of the line perpendicular to the one given and passing through the given point (5, 1) is
y - 1 = 0(x - 5) and
y - 1 = 0x - 0 and
y - 1 = 0 so
y = 1 is the equation you're looking for.
Answer:
8 / 17
Step-by-step explanation:
So cosine is adjacent ÷ hypotenuse.
Adjacent = 8
Hypotenuse = 17
8 / 17
Answer: (-1,4)
Step-by-step explanation:
y=-2x+2 y=7x+11 <----- substitute this equation for y in the
equation y=-2x+2
7x+11=-2x+2 Add 2x to both sides
9x+11=2 Subtract 11 from both sides
9x=-9 Divide both sides by 9
x=-1
y=-2(-1)+2 Plug in x to one of the equations, I chose y=-2x+2
y=2+2 because it was the easiest, then solve
y=4
Solution is (-1,4)
Answer:
2 1/2
Step-by-step explanation:
