Answer:
Step-by-step explanation:
Given that x = no of movies high school students watched is N(6.8, 1.8)
Sample size = 36 and hence std error = 1.8/6 = 0.3
(two tailed test)
Mean difference = 6.2-6.8 = -0.6
Test statistic z = -0.6/0.3= -2
p value = 0.02275
Since p <0.05 we reject H0.
There is evidence to show that college students watch fewer movies a month than high school students
To find the value of 1 out of all pieces divided, add the ratios.
8+1= 9
Now divide 72 by the total number.
72/9 = 8 (the value of one 1 unit)
Now to find the value of 8 units= 8*8 = 64
Value of 1 unit= 8
Answer:
we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
Step-by-step explanation:
Given data
n=29
mean of x = 49.98 mm
S = 0.14 mm
μ = 50.00 mm
Cl = 95%
to find out
Can we be 95% confident that machine calibrated properly
solution
we know from t table
t at 95% and n -1 = 29-1 = 28 is 2.048
so now
Now for 95% CI for mean is
(x - 2.048 × S/√n , x + 2.048 × S/√n )
(49.98 - 2.048 × 0.14/√29 , 49.98 + 2.048 × 0.14/√29 )
( 49.926757 , 50.033243 )
hence we say for μ = 50.00 mm we be 95% confident that machine calibrated properly with ( 49.926757 , 50.033243 )
ANSWER
The multiplication, CA is defined, and its dimension is 3×2
EXPLANATION
Matrix A is a 2x3 matrix.
Matrix C is a 3×2 matrix.
The product of the two matrices , CA, is defined if and only if the inner product of their dimension are the same.
The inner products are the same.
Hence the matrix multiplication, CA is defined and its dimension is the outer products.
