How do I prove this?

Find the volume of the solid.<br> 11 cm<br> 11 cm<br> 11 cm

grin007 [14]

Answer:1331cm

Step-by-step explanation:vol=lbh

11*11*11cm=1331cm

6 0

3 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago

Please help!<br> Please?

yuradex [85]

1. x - y
2. xy
3. y / x
4. x+y
5. y= x-6
6. 6x =y
7. y-x
8. x/y
9. x+y= 6
10. xy= 6

3 0

3 years ago

What is the cosine of angle F?

IceJOKER [234]

Cosine is adjacent/hypotenuse
The adjacent side to angle F is 60, and the hypotenuse is 61
Therfore, C) 60/61 would be the correct choice
hope this helps:)

8 0

4 years ago

Read 2 more answers

The heaviest freshwater fish caught in region A weighs 209 lb, and the heaviest freshwater fish caught in region B weighs 629 l

Colt1911 [192]

Answer:

$Region\ A= \frac{209}{2240}\\\\Region\ B= \frac{629}{2240}$

Step-by-step explanation:

The English ton, also known as the long ton, is equivalent to 2,240 pounds. Therefore, the fractional parts, of each of the two fish, of the English ton are:

Fish caught in region A:

$A= \frac{209}{2240}$

Fish caught in region B:

$B= \frac{629}{2240}$

Both fractions are irreducible.

4 0

3 years ago