Answer:
The 99% confidence interval estimate of the mean body temperature of all healthy humans is between 98.3ºF and 98.7ºF. 98.6°F is part of the confidence interval, which means that the sample suggests that this is a correct measure.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Z-table as such z has a p-value of
.
That is z with a pvalue of
, so Z = 2.575
Now, find the margin of error M as such
In which
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 98.5 - 0.2 = 98.3ºF.
The upper end of the interval is the sample mean added to M. So it is 98.5 + 0.2 = 98.7ºF.
The 99% confidence interval estimate of the mean body temperature of all healthy humans is between 98.3ºF and 98.7ºF. 98.6°F is part of the confidence interval, which means that the sample suggests that this is a correct measure.
Answer: 15g/mL
Step-by-step explanation:
Answer: About 21.64% of the fruit will be between 642 and 657 grams.
To solve this problem, we will have to find the probability for each z-score on the normal distribution. Then, subtract them to find the difference.
Lower End:
-9/27 = -0.33 for the z-score which is a probability of 0.3707
Upper End:
6/27 = 0.22 for the z-score which is a probability of 0.5871.
0.5871 - 0.3707 = 0.2164
Or about 21.64%