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3 years ago

What is the solution to the inequality 15y-9<36

Mathematics

1 answer:

artcher [175]3 years ago

6 0

Answer:

$\boxed{y$

Step-by-step explanation:

15y - 9 < 36 add 9 to both sides

15y < 45 divide both sides by 15

y < 3

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Please help with this question

leonid [27]

We know that $\sin(45)=\cos(45)$ and this is the only point when sin and cos are equal lengths. Because both $\sin(45),\cos(45)=\dfrac{\sqrt{2}}{2}$

Now if the sin of 30° is a half that would mean that cos of 60° is also a half.

Hope this helps.

r3t40

5 0

3 years ago

Suppose the height of an 18 year old boy is normally distributed with mean 187cm fifteen percent of 18 year old boys have height

BARSIC [14]

Answer:

the probability that two 18 year old boys chosen at random will have heights greater than 185cm is 0.403

Step-by-step explanation:

P( x > 193) = 0.15

= 1- p(x less than or equal 193)

= 1 -p( z < (x- u) /sigma)

= 1- p( z< (193 - 187)/ sigma)

= 1- p( z< 6/ sigma)

P(z< 6/sigma) = 1 - 0.15

P(z < 6/sigma)= 0.85

6/sigma =1.036

Sigma= 6/1.036

Sigma= 5.79

P( x> 185) = 1- p( x< 185)

= 1- p (z < (185- 187)/5.79)

= 1- p( z< -0.345)

= 1- 0.365

= 0.635

P (x> 185) = 0.635 × 0.635

=0.403

3 0

3 years ago

Last year at Sarah's bakery she sold 38 birthday cakes for $57 per cake . She spent 1/2 of that money on ingredients for baking

Andrei [34K]

Sarah spent $1,083 because $57*38=$2,166 and $2,166/2=$1083

7 0

3 years ago

the Wall Street Journal reported that automobile crashes cost United States $162 billion annually. The average cost per person f

Tanya [424]

Answer:

a) Margin of error = 166.311

b) sample size ≥ 62

Step-by-step explanation:

Given:

Average cost = $1599

Sample size = 50 persons

Standard deviation = $600

Confidence level is 95%

a) Margin of error = $z\frac{\sigma}{\sqrt{n}}$

Now for confidence level of 95% z-value = 1.96

Thus,

Margin of error = $1.96\frac{600}{\sqrt{50}}$

Margin of error = 166.311

b) For Margin of error ≤ 150

$z\frac{\sigma}{\sqrt{n}}$ ≤ 150

$1.96\frac{600}{\sqrt{n}}$ ≤ 150

$1.96\frac{600}{150}$ ≤ √n

√n ≥ 7.84

n ≥ 61.4656

Therefore,

sample size ≥ 62

6 0

3 years ago

10.204 round to the nearest hundredth

Nonamiya [84]

Answer:

Step-by-step explanation:

5 0

3 years ago