Which decimal represents the fraction of candles in this group that have flames

What is a close but easier numbers to estimate the answer to the problem

borishaifa [10]

You forgot to put the problem but choose answers that will divide evenly

3 0

3 years ago

SelectTWO expressions that are equivalent to 8(x + 5y).

JulsSmile [24]

Answer:

The bottom two

8 0

2 years ago

How do you know that 21 over 30 is greater than 2 over 3

Bond [772]

The problem deals with fractions comparison, lets do it:
21/30 > 2/3
we begin solving:
21 > (2/3)*30
21 > 2*10
21 > 20
therefore the proposed inequality is true, 21/30 > 2/3

You can solve as well getting same denominator for both fractions and comparing directly, in this case we need to get 2/3 to be divided by 30:
2/3 = (10/10)(2/3) = 20/30
So we have:
21/30 > 2/3
which is equal to:
21/30 > 20/30
and we compare directly because both fractions are divided by the same number, and we can see that the inequality is true.

7 0

3 years ago

The velocity of an automobile starting from rest is given by the equation below, where v is measured in feet per second and t is

podryga [215]

Answer:

(a) $0.408m/sec^2$

(b) $0.134m/sec^2$

(c) $0.039m/sec^2$

Step-by-step explanation:

We have given velocity as function of t $v(t)=\frac{85t}{(8t+14)}$

Acceleration is equation rate if change of velocity with respect to time

So $a=\frac{dv}{dt}=\frac{(8t+14)85-85t\times 8}{(8t+14)^2}$

(a) Acceleration at t = 5 sec

$a=\frac{(8\times 5+14)85-85\times 5\times 8}{(8\times 5+14)^2}=0.408m/sec^2$

(b) Acceleration at t = 10 sec

$a=\frac{(8\times 10+14)85-85\times 10\times 8}{(8\times 10+14)^2}=0.134m/sec^2$

(c) Acceleration at t = 20 sec

$a=\frac{(8\times 20+14)85-85\times 20\times 8}{(8\times 20+14)^2}=0.039m/sec^2$

5 0

3 years ago

So here is a theoretical question. Let L1 and L2 be linear transformation from a vector space V into Vector space W. Let {v1,v2,

noname [10]

if v belongs to V, then we can find scalars a1,a2,...,an, such that v=a1*v1+a2*v2+...+an*vn, L1(v)=L1(a1*v1+a2*v2+...+an*vn) =a1*L1(v1)+a2*L1(v2)+...+an*L1(vn) =a1*L2(v1)+a2*L2(v2)+...+an*L2(vn) =L2(a1*v1+a2*v2+...+an*vn) =L2(v)

6 0

2 years ago