Answer: -144.1226
Step-by-step explanation:
The one near the five is in the hundreds place and the one near the 4 is in the tenth place.
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B. Angle B= Angle E
As this would only prove the AAA Similarity theorem, but not any Congruence Rule
(not <em>a</em> or not <em>b</em>) implies <em>c</em> <==> not (not <em>a</em> or not <em>b</em>) or <em>c</em>
so negating gives
not [(not <em>a</em> or not <em>b</em>) implies <em>c</em>] <==> not[ not (not <em>a</em> or not <em>b</em>) or <em>c</em>]
which we can simplify somewhat to
not (not (not <em>a</em> or not <em>b</em>)) and not <em>c</em>
(not <em>a</em> or not <em>b</em>) and not <em>c</em>
(not <em>a</em> and not <em>c</em>) or (not <em>b</em> and not <em>c</em>)
not (<em>a</em> or <em>c</em>) or not (<em>b</em> or <em>c</em>)
not ((<em>a</em> or <em>c</em>) and (<em>b</em> or <em>c</em>))
not ((<em>a</em> and <em>b</em>) or <em>c</em>)
Answer:
99.87% of cans have less than 362 grams of lemonade mix
Step-by-step explanation:
Let the the random variable X denote the amounts of lemonade mix in cans of lemonade mix . The X is normally distributed with a mean of 350 and a standard deviation of 4. We are required to determine the percent of cans that have less than 362 grams of lemonade mix;
We first determine the probability that the amounts of lemonade mix in a can is less than 362 grams;
Pr(X<362)
We calculate the z-score by standardizing the random variable X;
Pr(X<362) = 
This probability is equivalent to the area to the left of 3 in a standard normal curve. From the standard normal tables;
Pr(Z<3) = 0.9987
Therefore, 99.87% of cans have less than 362 grams of lemonade mix
