The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
Answer:
B.
Step-by-step explanation:
The absolute value of 0 is 0 so 0 = 0 is true.
810
.....+27+31+35+39+43+47+51+55+59+63+67+71+75+79
Answer:
5130
Step-by-step explanation:
You just multiply 513 by 10 to get 5130.
You can check this answer by just seeing if it fits the requirements, which it does. Making it the correct answer.
