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To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
45x97=4365 hours, number of hours multiply by n of enmp
A sword is Saskatchewan. Mdkdodn idioms has nsito day you can come to sleep early tomorrow and you yo me
Sandy ran 5 ½ during the second hour.
- Total amount Sandy used to jog for 2 hours = 13 miles
- Amount Sandy used to run in the 1st hour = 7 ½
<h2>Further Explanation</h2>
Therefore the amount Sandy used to run in the 2nd hour = Total amount Sandy used to jog for 2 hours – Amount Sandy used to run in the 1st hour
= 13 – 7 ½ (and can be expressed as 7 + ½)
= 13 – (7 + ½)
= 13 – 7 – ½
= 6 – ½ (otherwise expressed as 6/1 – 1/2)
= (6 x 2) – (1 x 1) / 2
= (12) – (1) / 2
= 12 – 1 / 2
= 11/2
= 5 ½
Hence, Sandy ran 5 ½ miles during the second hour.
Based on the above expression, it is observed that there is an element of fractions in the math problem. Also, BODMAS was clearly used to derive the solution to the given question.
Recall, 13 – (7 + ½). The mathematical signs, (–) and (+) were multiplied; one of mathematics rule states that – x + = –; thus 13 – 7 – ½
Notably, fractions deal with denominators and numerators; and in these questions, with the help of BODMAS, they (6/1 – 1/2) were used to factor each other out to derive the final answer 5 ½.
LEARN MORE:
KEYWORDS:
- bodmas
- fractions
- mathematical sign
- denominators
- numerators
