I believe the answer would be yes, because as the radius increases, the circumference of the object also increases
Answer:
slope = - 
Step-by-step explanation:
Calculate the slope m using the slope formula
m = 
with (x₁, y₁ ) = (- 5, 0) and (x₂, y₂ ) = (0, - 7 ) ← 2 points on the line
m =
=
=
= - 
First we'll substitute
with 

Then we can separate this.

Then we'll solve this.



Then we'll plug in to find the extraneous solutions (if any)

Answer: multiple the length vu the width
Step-by-step explanation: