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3 years ago

The simplified form of (2x+1)(3x−2)/24x 2−4x −8

1 answer:

8 0

$\frac{(2x+1)(3x-2)}{24x^{2}-4x-8} = \frac{(2x+1)(3x+2)}{4(6x^{2}-x-2)} = \frac{(2x+1)(3x+2)}{4(6x^{2}-4x+3x-2)} = \frac{(2x+1)(3x+2)}{4[2x(3x-2)+(3x-2)]} = \\ \\ = \frac{(2x+1)(3x+2)}{4(2x+1)(3x-2)} = \frac{3x+2}{4(3x-2)} = \frac{3x+2}{12x-8}$

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