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3 years ago

How long will it take to go 150 km traveling 30 km/hr

2 answers:

8 0

Simple...

You have 150 km..you're going 30 km per hour...

$\frac{150}{30} =5$

This means you will travel 150 km in 5 hours.

Thus, your answer.

11Alexandr11 [23.1K]3 years ago

7 0

Hello there.

How long will it take to go 150 km traveling 30 km/hr

150/30=5
5 hours

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Answer:

Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

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Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

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simplify

$sin(\alpha)=\frac{4}{7}$

therefore

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Part B) Find $tan(\alpha)\ and\ cot(\beta)$

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If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

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$tan(\alpha)=cot(\beta)$

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Applying the Pythagorean Theorem

Let

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$14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132$

$x=\sqrt{132}\ units$

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$x=2\sqrt{33}\ units$

Find the value of $tan(\alpha)$ in the right triangle of the figure

$tan(\alpha)=\frac{8}{2\sqrt{33}}$ ---> opposite side divided by the adjacent side angle alpha

simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

$tan(\alpha)=\frac{4}{\sqrt{33}}$

$tan(\beta)=\frac{4}{\sqrt{33}}$

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If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

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slavikrds [6]

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