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Kipish [7]
3 years ago
12

How long will it take to go 150 km traveling 30 km/hr

Mathematics
2 answers:
Pani-rosa [81]3 years ago
8 0
Simple...

You have 150 km..you're going 30 km per hour...

\frac{150}{30} =5

This means you will travel 150 km in 5 hours.

Thus, your answer.
11Alexandr11 [23.1K]3 years ago
7 0
Hello there.

<span>How long will it take to go 150 km traveling 30 km/hr

150/30=5
</span><span>5 hours</span>
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Can somebody pls help mee
Leto [7]

Answer:

the answer is 8

Step-by-step explanation:

add all four in n the half of the others 2 =1

8 0
3 years ago
I need help on this one
Stella [2.4K]

Answer:

With what? I don't see the question.....

4 0
3 years ago
Please anyone to show me how this mathematics question is done..please
irinina [24]

9514 1404 393

Answer:

  (i) 55.59 km/h

  (ii) 3600 nautical miles ≈ 6670.8 km

  (iii) 30°N 29.3°E

Step-by-step explanation:

(i) The speed in km/h requires a units conversion.

  (30 kt/h)(1.853 km/kt) = 55.59 km/h

__

(ii) Here, we assume we're interested in the <em>distance traveled</em>. If the course is "due east", we presume that means it follows the 30° latitude line, so is not the shortest route between A and B. That is, the distance from A to B will be different from the distance traveled. (The shortest route from A to B is along a great circle.)

  distance = speed × time

  distance = (30 kt/h)(120 h) = 3600 nautical miles

  = (55.59 km/h)(120 h) = 6670.8 km

__

(iii) The radius of the 30° latitude line is ...

  (6370 km)(cos(30°)) = 3185√3 km ≈ 5516.58 km

The relationship between arc length (s) and central angle (α) is ...

  s = rα

So, the change in the vessel's longitude is ...

  α = (6670.8 km)/(5516.58 km) ≈ 1.20923 radians ≈ 69.28°

Then town B has longitude ...

  40°W -69.3° = -29.3°W = 29.3°E

The position of town B is about 30°N 29.3°E.

_____

<em>Additional comment</em>

The route supposedly taken by this sea vessel is from the middle of the North Atlantic to a town in northern Egypt, through the northern Sahara desert. The eastern end point is shown in the attachment.

Some spherical trigonometry is involved if you want to find the end point of the great-circle route of the same length.

5 0
3 years ago
Solve for b. 5 + 2b = 9 Show your work for each step as you solve for b.
Dahasolnce [82]

Answer:

\boxed{\sf{b=2}}

Step-by-step explanation:

Isolate the b from one side of the equation.

<u>First, subtract by 5 from both sides.</u>

\sf{5+2b-5=9-5}

<u>Solve.</u>

<u />

<u>Subtract.</u>

9-5=4

2b=4

<u>Divide by 2 from both sides.</u>

2b/2=4/2

<u>Solve.</u>

<u />

<u>Divide the numbers from left to right.</u>

4/2=2

\Longrightarrow \boxed{\sf{b=2}}

Therefore, the correct answer is b=2.

I hope this helps, let me know if you have any questions.

6 0
2 years ago
Read 2 more answers
Help me!!!!!!!!!!!!!!!!!!!!!
marissa [1.9K]

Answer:

\frac{7}{3} and \:  \frac{8}{3}

Step-by-step explanation:

so let's start with what we know:

2 \frac{1}{3}  \times 2 \frac{2}{3}

now to get it into non mixxed numbers:

2*3 = 6

6+1

_____

\frac{7}{3}

2*3=6

6+2=8

______

\frac{8}{3}

now to cross mutiply them:

7*3

7 0
3 years ago
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