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motikmotik
3 years ago
10

Suppose that daycare costs are normally distributed with a mean equal to $10,000 a year and a standard deviation equal to $2,000

.
what percentage of daycare cost over $10,000?
what percentage of daycare cost between $8,000 and $12,000?
what percentage of daycare cost between $6,000 and $14,000?
Mathematics
1 answer:
notka56 [123]3 years ago
6 0

Answer:

50%, 68.26%, 95.54%

Step-by-step explanation:

Let X be the day care costs

X is N(10000, 2000)

Since normal distribution is symmetrical about the mean we get

above 10000, exactly 50% of day care cost would be .

Between 8000 and 12000,

=P(8000

Between 6000 and 14000

P(6000%

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19 dollars

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<h2>Buckle up! This is a good one!</h2>

First we have to find the line that goes trough the two points. And it has the form :

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<u />

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The revenue is price times quantity, since price is y and quantity is x, we get

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R'(x)=-\frac{1}{1500} x+38=0\\38=\frac{1}{1500} x\\38*1500=x=57000

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y= -\frac{1}{3000}x + 38\\y= -\frac{1}{3000}(57000) + 38\\y= -19 + 38\\y=19

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