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nalin [4]
3 years ago
6

Find the 3rd term of an arithmetic sequence with t5 = 3 and t7 = 7.

Mathematics
1 answer:
Usimov [2.4K]3 years ago
7 0
Tn=t1+d(n-1)
t5-t7=2d
7-3=4
2d=4
d=2

tn=t1+2(n-1)
t5=3
3=t1+2(5-1)
3=t1+2(4)
3=t1+8
minus 8
-5=t1

tn=-5+2(n-1)
t3=-5+2(3-1)
t3=-5+2(2)
t3=-5+4
t3=-1

3rd term is -1
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find the smaller of 2 consecutive integers,x, if the sum of the smaller and 6 times the larger is -29
AnnyKZ [126]

Answer:-  The smaller integer is -5.


Explanation:-

Let the first consecutive integer be x and the second consecutive integer be x+1.

According to the given question:-

x+6(x+1)= -29

⇒x+6x+6= -29   [distributive law]

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3 0
3 years ago
How many 1/5s are in 1?
atroni [7]

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Step-by-step explanation:

7 0
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Murljashka [212]
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