Find the 3rd term of an arithmetic sequence with t5 = 3 and t7 = 7.

1 answer:

7 0

Tn=t1+d(n-1)
t5-t7=2d
7-3=4
2d=4
d=2

tn=t1+2(n-1)
t5=3
3=t1+2(5-1)
3=t1+2(4)
3=t1+8
minus 8
-5=t1

tn=-5+2(n-1)
t3=-5+2(3-1)
t3=-5+2(2)
t3=-5+4
t3=-1

3rd term is -1

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An angle whose measure is _____ is rotated more than halfway around a circle

zaharov [31]

The correct answer is 60⁰.

Step-by-step explanation:

An angle whose measure is 60⁰ is rotated more than halfway around a circle.
Since, we have to find the measure of angle.
As we already know that the angle of rotation about a circle is 360° therefore we have to find more than halfway of this angle.

Considering that an angle is rotated more than halfway around a circle be $\frac{1}{6}$

Multiplying $\frac{1}{6}$ with 360⁰
Therefore, it can show as $\frac{1}{6}$ ×360⁰
Which gives the result to be 60⁰
Hence, when an angle is measured 60⁰, it is rotating more than halfway around a circle.
A single rotation around a circle is equal to 360 degrees.
The measurement of an angle shows the magnitude and direction of the rotation of the angle from its initial position to the final position.
If the rotation is in a counterclockwise direction, it has an angle with positive measure. If the rotation is clockwise, it has an angle which gives negative measure.