3 years ago

Is this answer correct if not send help

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

5 0

I believe that is correct

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Let

Digiron [165]

What I gather from the question is that $X$ has second moment $E(X^2)=81$ and variance $V(X) = 58$ , and you're asked to find the expectation and variance of the random variable $Y=2X+10$ .

From the given second moment and variance, we find the expectation of $X$ :

$V(X) = E(X^2) - E(X)^2 \implies E(X) = \sqrt{E(X^2) - V(X)} = \sqrt{23}$

Expectation is linear, so

$E(Y) = E(2X+10) = 2 E(X) + 10 = \boxed{2\sqrt{23} + 10}$

Using the same variance identity, we have

$V(Y) = V(2X+10) = E((2X+10)^2) - E(2X+10)^2$

and

$E((2X+10)^2) = E(4X^2 + 40X + 100) = 4E(X^2) + 40E(X) + 100 = 424 + 40\sqrt{23}$

so that

$V(Y) = V(2X+10) = (424 + 40\sqrt{23}) - (2\sqrt{23} + 10)^2 = \boxed{232}$

Alternatively, we can use the identity

$V(aX+b) = a^2 V(X) \implies V(2X+10) = 4V(X) = 232$

5 0

2 years ago

What’s the answer for 6?

horrorfan [7]

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3 years ago

10. Consider the diagram below.<br> A. solve for x<br> B. Solve for y

anastassius [24]

Answer:

x=42 y=38

Step-by-step explanation:

hope it helps, please thank, review, and mark as brainliest! tysm!

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3 years ago

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zloy xaker [14]

The probability of it is 2/5

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Rashid [163]

Zero point (or decimal) one seven.

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3 years ago

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