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Whitepunk [10]
2 years ago
6

There are 27 campers. This is nine times as many as the number of counselors. How many counselors are there?

Mathematics
1 answer:
musickatia [10]2 years ago
3 0
Well, you would have to multiply 27 by 9 to get 243, which is the answer.
You might be interested in
In Hillsboro's wig shop, 1/2 of the wigs are blonde and 1/12 of the wigs are brunette. What fraction of the wigs are either blon
ella [17]

Answer:

7/12

Step-by-step explanation:

So, the probability of picking up a blonde wig = 1/2

The probabiliy of picking up a brunette wig = 1/12

The question asks to find th eprobability of picking up either of these types of wigs =

1/2 + 1/12

= 6/12 + 1/12 ( LCM of 12 and 1 is 12 )

= 7/12

Hope this helps

3 0
2 years ago
MATH PERCENTAGE QUESTION HELP!
lubasha [3.4K]

Answer:

68.5% seats filled

76% points earned

Step-by-step explanation:

<h3><u>General outline</u></h3>
  1. Identify the whole and the part
  2. Change ratio into a percentage

<h3><u>Ratios</u></h3>

Percentages are formed when one finds a ratio of two related quantities, usually comparing the first partial quantity to the amount that "should" be there.

\text{ratio}=\dfrac {\text{the "part"}}{\text{the whole}}

For instance, if you have a pie, and you eat half of the pie, you're in effect imagining the original pie (the whole pie) cut into two equal pieces, and you ate one of them (the "part" of a pie that you ate).  To find the ratio of pie that you ate compared to the whole pie, we compare the part and the whole:

\text{ratio}=\dfrac {\text{the number of "parts" eaten}}{\text{the number of parts of the whole pie}}

\text{ratio}=\dfrac {1}{2}

If you had instead eaten three-quarters of the pie, you're in effect imagining the original pie cut into 4 equal pieces, and you ate 3 of them.

\text{ratio}=\dfrac {\text{the number of "parts" eaten}}{\text{the number of parts of the whole pie}}

\text{ratio}=\dfrac {3}{4}

There can be cases where the "part" is bigger than the whole.  Suppose that you are baking pies and we want to find the ratio of the pies baked to the number that were needed, the number of pies you baked is the "part", and the number of pies needed is the whole.  This could be thought of as the ratio of project completion.

If we need to bake 100 pies, and so far you have only baked 75, then our ratio is:

\text{ratio}=\dfrac {\text{the number of "parts" made}}{\text{the number of parts of the whole order}}

\text{ratio}=\dfrac {75}{100}

But, suppose you keep baking pies and later you have accidentally made more than the 100 total pies.... you've actually made 125 pies.  Even though it's the bigger number, the number of pies you baked is still the "part" (even though it's bigger), and the number of pies needed is the whole.

\text{ratio}=\dfrac {\text{the number of "parts" made}}{\text{the number of parts of the whole order}}

\text{ratio}=\dfrac {125}{100}

<h3><u>Percentages</u></h3>

To find a percentage from a ratio, there are two small steps:

  1. Divide the two numbers
  2. Multiply that result by 100 to convert to a percentage

<u>Going back to the pies:</u>

When you ate half of the pie, your ratio of pie eaten was \frac{1}{2}

Dividing the two numbers, the result is 0.5

Multiplying by 100 gives 50.  So, the percentage of pie that you ate (if you ate half of the pie) is 50%

When you ate three-quarters of the pie, the ratio was \frac{3}{4}

Dividing the two numbers, the result is 0.75

Multiplying by 100 gives 75.  So, the percentage of pie that you ate (if you ate three-quarters of the pie) is 75%.

When you were making pies, and 100 pies were needed, but so far you'd only baked 75 pies, the ratio was \frac{75}{100}

Dividing the two numbers, the result is 0.75

Multiplying by 100 gives 75.  So, the percentage of the project that you've completed at that point is 75%.

Later, when you had made 125 pies, but only 100 pies were needed, the ratio was \frac{125}{100}

Dividing the two numbers, the result is 1.25

Multiplying by 100 gives 125%.  So, the percentage of pies you've made to complete the project at that point is 125%.... the number of pies that you've made is more than what you needed, so the baking project is more than 100% complete.

<h3><u>The questions</u></h3>

<u>1.   27400 spectators n a 40000 seat stadium percentage.</u>

Here, it seems that the question is asking what percentage of the stadium is full, so the whole is the 40000 seats available, and the "part" is the 27400 spectators that have come to fill those seats.

\text{ratio}=\dfrac {\text{the number of spectators filling seats}}{\text{the total number of seats in the stadium}}

\text{ratio}=\dfrac {27400}{40000}

Dividing gives 0.685.  Multiplying by 100 gives 68.5.  So, 68.5% of the seats have been filled.

<u>2.   an archer scores 95 points out of a possible 125 points percentage</u>

Here, it seems that the question is asking what percentage of the points possible were earned, so the whole is the 125 points possible, and the "part" is the 95 points that were earned.

\text{ratio}=\dfrac {\text{the number of points earned}}{\text{the total number of points possible}}

\text{ratio}=\dfrac {95}{125}

Dividing gives 0.76.  Multiplying by 100 gives 76.  So, 76% of points possible were earned.

8 0
2 years ago
Rhianna says she can draw different functions that have the same x‑intercepts and the same domain and range. Her teammates say,
qwelly [4]

In both cases there are more than one possible function sutisfying given data.

1. If

  • x‑intercepts are (–5, 0), (2, 0), and (6, 0);
  • the domain is –5 ≤ x ≤ 7;
  • the range is –4 ≤ y ≤ 10,

then (see attached diagram for details) you can build infinetely many functions. From the diagram you can see two graphs: first - blue graph, second - red graph. Translating their maximum and minimum left and right you can obtain another function that satisfies the conditions above.

2. If

  • x‑intercepts are (–4, 0) and (2, 0);
  • the domain is all real numbers;
  • the range is y ≥ –8,

then you can also build infinetely many functions. From the diagram you can see two graphs: first - blue graph, second - red graph. Translating their  minimum left and right you can obtain another function that satisfies the conditions above.

Note, that these examples are not unique, you can draw a lot of different graphs of the functions.

Answer: yes, there are more than one possible function

6 0
3 years ago
03.03 mc) find the ordered pairs for the x- and y-intercepts of the equation 5x − 6y = 30 and select the appropriate option belo
Archy [21]
5x - 6y = 30

to find x intercept, sub in 0 for y
5x - 6(0) = 30
5x = 30
x = 30/5
x = 6......so the x intercept is (6,0)

to find the y intercept, sub in 0 for x
5(0) - 6y = 30
-6y = 30
y = 30/-6
y = -5...so the y intercept is (0,-5)
6 0
2 years ago
Given that the solution set to a system of three linear equations is a line, which of the following is true about the system?
Setler79 [48]

The <em><u>correct answer</u></em> is:

d) The system can only be dependent and consistent.

Explanation:

In order for the solution to a system of equations to be a line, this means that the lines must lie on top of one another.  This means they are the same line; the system is consistent since there is at least one solution, and dependent since all of the points in one equation work for the other equations as well.

8 0
2 years ago
Read 2 more answers
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