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goblinko [34]
3 years ago
9

14 4/9+ 25 1/6+ 7 11/18=

Mathematics
2 answers:
Nina [5.8K]3 years ago
4 0

Answer:

47 2/9

Step-by-step explanation:

( 14 + 25 + 7) + ( 4/9 + 1/6 + 11/18)

46 + 11/9

46 + 1 2/9

47 2/9

zavuch27 [327]3 years ago
3 0

Answer:

47 2/9

hope this help :)

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Name a pair of overlapping congruent triangles in each diagram. State whether the triangles are congruent by SSS, SAS, ASA, AAS,
MariettaO [177]

Answer:

ΔPTS≅ΔRTA by AAS axiom of congruency

Step-by-step explanation:

Consider ΔPQA and ΔRQS

∠PQA=∠RQS     (Vertically Opposite Angles)

∠QAP=∠QSR     (Complementary of two equal angles, ∠RAT and∠PST)

Due to angle sum property of a triangle, we come to the conclusion that

∠APQ=∠SRQ

Consider ΔPTS and ΔRTA

TA=TS  (Given)

∠RAT=∠PST(Given)

∠APQ=∠SRQ (Proved above)

Therefore, ΔPTS≅ΔRTA by AAS axiom of congruency.

8 0
4 years ago
HELPPPPPPPPPPPPMEEEEEEE
Alexus [3.1K]

Answer:

I'm pretty sure it is 21

4 0
3 years ago
If y varies inversely as x and y=3 when x=14, find x when y=6​
alukav5142 [94]
X=7 What you can do is look at the first two values given, and make them x1 and y1. Then your next value here is y2.

So x1 is 14, and y1 is 3. y2 becomes 6. X2 is unknown.

Then make the formula: x1/y2 is equal to x2/y1
(You are setting two fractions equal to each other)

That makes 14/6=X/3. When we cross multiply, we find that x=7.
3 0
3 years ago
2.
Novay_Z [31]

Answer:

4096

Step-by-step explanation:

3 0
3 years ago
Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0
Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . x^{2}e^{-x}+2y^{2}-xy"

Answer : \frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

Step-by-step explanation:

From the expression  x^{2}e^{-x}+2y^{2}-xy" y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\

for the expression \frac{d}{dx}(x^{2}e^{-x}) we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\.

if we make dy/dx  subject of formula we arrive at

(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

5 0
4 years ago
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