Question

In 1970 the male incarceration rate in the U.S. was approximately 190 inmates per 100,000 population. In 2008 the rate was 960 inmates per 100,000 population. What is the percent increase in the male incarceration rate during this period?

Answer 1

Answer:

40.53%

Step-by-step explanation:

$Percentage Increase = \frac{New Value - Old Value}{Old Value}\times100$

Here, New Value = 960÷100,000

Old Value = 190÷ 100,000

∴ $Percentage Increase = \dfrac{\frac{960}{100,000} - \frac{190}{100 ,000} }{\frac{190}{100,000}}\times100$

⇒ Percentage Increase = 40.53%

Thus, percent increase in the male incarceration rate during given period is 40.53%.