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Mama L [17]
3 years ago
14

What is the equation of the line in slope-intercept form?

Mathematics
1 answer:
USPshnik [31]3 years ago
4 0

Answer:

y=mx + b (slope intercept form) m= slope, b =y-intercept

slope=rise/ run

Step-by-step explanation:

The slope intercept form is a line (straight line)

y = 3x - 7  slope 3 (rise=3, run = 1), y-intercept = -7

y = - 1 3 x + 7 slope -13 , y-intercept = 7

y=-3x - 7 slope -3, y-intercept = -7

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Type the correct answer in the box.
gogolik [260]

Answer:

en español porfa no ablo ingles

7 0
3 years ago
A radioactive substance decays exponentially: The mass at time t is m(t) = m(0)ekt, where m(0) is the initial mass and k is a ne
velikii [3]

Answer:

M = 1/0.000121 = 8264.5 years

Step-by-step explanation:

M = − k ∫∞₀ teᵏᵗdt

To obtain this mean life, we'll use integration by parts to integrate the function ∫ teᵏᵗdt

∫udv = uv - ∫ vdu

u = t

du/dt = 1

du = dt

∫ dv = ∫ eᵏᵗdt

v = eᵏᵗ/k

∫udv = ∫ teᵏᵗdt

uv = teᵏᵗ/k

∫ vdu = eᵏᵗ/k

∫ teᵏᵗdt = (teᵏᵗ/k) - ∫eᵏᵗ/k

But, ∫eᵏᵗ/k = (1/k) ∫eᵏᵗ = (1/k²) eᵏᵗ = eᵏᵗ/k²

∫ teᵏᵗdt = (teᵏᵗ/k) - eᵏᵗ/k²

The rest of the calculation is done on paper in the image attached to this question

3 0
3 years ago
The circumference of a
timama [110]

9514 1404 393

Answer:

  • 160,000 m²
  • 16 ha

Step-by-step explanation:

The side length of a square is 1/4 of the perimeter, so the side length of the square orchard is (1600 m)/4 = 400 m.

The area of a square is the square of the side length, so the area of the orchard is (400 m)² = 160,000 m².

A hectare is 10,000 m², so the area of the orchard in hectares is ...

  16·(10,000 m²) = 16 ha

3 0
3 years ago
646 is 85% of what number?
Lilit [14]

Let the number be y

The statement can be interpreted as

85% of y = 646

\begin{gathered} \text{ }\frac{85}{100}\text{ x  y = 646} \\ 85y\text{ = 64600} \\ y=\frac{64600}{85} \\ y=760 \\ \text{  The number is 760} \end{gathered}

8 0
1 year ago
Please help with this question
My name is Ann [436]

In a symmetric histogram, you have the same number of points to the left and to the right of the median. An example of this is the distribution {1,2,3,4,5}. We have 3 as the median and there are two items below the median (1,2) and two items above the median (4,5).

If we place another number into this distribution, say the number 5, then we have {1,2,3,4,5,5} and we no longer have symmetry. We can fix this by adding in 1 to get {1,1,2,3,4,5,5} and now we have symmetry again. Think of it like having a weight scale. If you add a coin on one side, then you have to add the same weight to the other side to keep balance.

4 0
3 years ago
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