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lions [1.4K]
3 years ago
11

Victoria recently switched to a new electric company. If she uses between 0 and 400 kilowatt-hours (kWh) of electricity per mont

h, the cost is a set price of $30. If she uses 400 kWh or more per month, the price is $0.097 per kWh.
Mathematics
1 answer:
Gekata [30.6K]3 years ago
7 0

Answer:

see the explanation

Step-by-step explanation:

<em><u>The question is </u></em>

Identify the domain and the range, using words and inequalities

Let

x -----> the number of kilowatt-hours (kWh) of electricity per month

y ----> the price per month

we know that

Part 1) For the value of x between 0 kWh and 400 kWh

0\ kWh \leq x < 400\ kWh

The price is equal to

y=\$30

therefore

The domain is the interval ------> [0,400)

The domain is all real numbers greater than or equal to 0 kWh  and less than 400 kWh

The range is ($30)

The range is equal to $30

Part 2) For the value of x equal to 400 kWh or more per month

x\geq 400\ kWh

The domain is the interval -----> [400, infinite)

The domain is all real numbers greater than or equal to 400 kWh

The price is

y=0.097x

<em>Find the range</em>

For x=400 kWh

y=0.097(400)=\$38.8

so

y\geq \$38.8

The range is the interval -----> [38.8, infinite)

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You have $25 to buy 6 fishing lures. Write and solve an inequality that represents the prices you can pay per fishing lure.
Rus_ich [418]

We are given that we have $25 to pay for 6 fishing lures.

We can make an equality for this as follows:

Suppose price of one fishing lure is x dollars.

So we will use unitary method to find price of 6 fishing lures.

Price of 6 fishing lures = 6 * ( price of one fishing lure) = 6* x = 6x

Now we only have 25 dollars with us, so the price of 6 fishing lures has to be less than or equal to 25 dollars.

So creating an inequality,

6x\leq25

Now in order to find price for one fishing lure, we have to solve this for x.

Dividing both sides by 6 we have,

x\leq\frac{25}{6}

Converting to decimal,

x\leq4.167

Answer : The price of one fishing lure must be less than or equal to $4.167

6 0
3 years ago
Help me plss need help with theses three
fiasKO [112]
interior angle of a regular 18-gon.
It is easier to calculate the exterior angle of a regular polygon of n-sides (n-gon) by the relation
exterior angle = 360/n
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The value of each interior angle is therefore the supplement, or
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Naming of a 9-gon
A polygon with 9 vertices is called a nonagon (in English) or enneagon (French ennéagone, but the English version is sometimes used)
You had a good start with the correct answer.

Exterior angle of a 15-gon
The exterior angle of a 15-gon can be calculated using the relation given in the first paragraph, namely
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4 0
3 years ago
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masha68 [24]

Answer:

I believe its Orange

Step-by-step explanation:

2/3 is greater than all other ratios

5 0
3 years ago
Read 2 more answers
5+7k&gt;=-30 and -4k +4&gt;20​
Slav-nsk [51]

Answer:

\large\boxed{-5\leq k

Step-by-step explanation:

5+7k\geq-30\ \wedge\ -4k+4>20\\\\5+7k\geq-30\qquad\text{subtract 5 from both sides}\\7k\geq-35\qquad\text{divide both sides by 7}\\\boxed{k\geq-5}\\\\-4k+4>20\qquad\text{subtract 4 from both sides}\\-4k>16\qquad\text{change the signs}\\4k

7 0
3 years ago
Can somebody help me with this please?
Svetach [21]
Multiply both sides by -4/7
x = 40 \times ( \frac{ - 4}{7} ) \\ x =  \frac{ - 160}{7}
7 0
3 years ago
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