Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
The correct graph would be the first one
Answer: g = 42
Step-by-step explanation:
g/3 + 11 = 25
First, subtract 11 to both sides
g/3 = 14
Then, multiply 3 to both sides to get rid of the fraction
g=42
Hey
Answer: 4
How do you find that out?
Divide the two numbers on the right, 36 and 8.
36/8=4
7 * 4 + 8 = 36
Hope this helped
