Question

Jen buys sesame bagels and plain bagels. If the ratio of sesame to plain is 1:3 and Jen bought 2 dozen bagels, what percent of bagels are plain? How many bagels are plain? Suppose each plain bagel has 0.53 gram of salt, and each sesame bagel has 0.65 gram. Use a percent to compare the amount of salt in a plain bagel to that in a sesame bagel.

Answer 1

Answer:

The number of plain bagels are 18 and it is 75% of the total bagels .

The amount of salt in a plain bagel to that in a sesame bagel is 81.5% .

Step-by-step explanation:

Formula

$Percentage = \frac{Part\ value\times 100}{Total\ value}$

As given

Jen buys sesame bagels and plain bagels. If the ratio of sesame to plain is 1:3 and Jen bought 2 dozen bagels .

As one dozens contains 12 items .

Thus

Total number of bagels bought by Jen = 2 × 12

                                                                 = 24

Let us assume that the x be the scalar multiple of sesame bagels and plain bagels .

Number of sesame bagels = 1x

Number of plain bagels = 3x

Than the equation becomes

x + 3x = 24

4x = 24

$x = \frac{24}{4}$

x = 6

Thus

Number of plain bagels = 3 × 6

                                        = 18

Part value = 18

Total value = 24

Putting all the values in the formula

$Percentage = \frac{18\times 100}{24}$

$Percentage = \frac{1800}{24}$

Percentage = 75 %

Therefore the number of plain bagels are 18 and it is 75% of the total bagels  .

As given

Suppose each plain bagel has 0.53 gram of salt, and each sesame bagel has 0.65 gram.

Part value = 0.53 grams

Total value = 0.65 grams

Putting all the values in the formula

$Percentage = \frac{0.53\times 100}{0.65}$

$Percentage = \frac{5300}{65}$

Percentage = 81.5 %

Therefore the amount of salt in a plain bagel to that in a sesame bagel is 81.5% .