Answer:
56 cm^2
Step-by-step explanation:
Surface area is just finding the areas of each face in a figure. As we are given a net of a figure, it is much easier for us to calculate it.
Area of square base (side^2)
4^2 = 16 cm^2
Area of ONE triangular face (1/2 x b x h):
1/2 x 4 x 5 = 10 cm^2
Multiply that by 4 because we have 4 triangular faces: 10 cm^2 x 4 = 40 cm^2
ADD all the areas of triangles and square:
16 cm^2 + 40 cm^2 = 56 cm^2
HOPE THIS HELPS
Have a nice day!
Answer:
I do not know how it wants the answer, but it is -4.1 repeating.
I am guessing you meant solve for z too? If there are multiple choice I can help choose the right one.
Step-by-step explanation:
-32>5+9z
subtract 5 from both sides
-37>+9z
then divide 9 from both sides
-4.1111 repeating > z
It will be the second option i believe
Split up the interval [2, 5] into
equally spaced subintervals, then consider the value of
at the right endpoint of each subinterval.
The length of the interval is
, so the length of each subinterval would be
. This means the first rectangle's height would be taken to be
when
, so that the height is
, and its base would have length
. So the area under
over the first subinterval is
.
Continuing in this fashion, the area under
over the
th subinterval is approximated by
, and so the Riemann approximation to the definite integral is
and its value is given exactly by taking
. So the answer is D (and the value of the integral is exactly 39).
Answer:
The cup can hold 497.17 in³ of liquid.
Step-by-step explanation:
The shape of the glass can be divided in two figures, the first one is a cilinder with radius 5 in and height 3 in, while the second is a half sphere with radius 5 in. Therefore in order to calculate the volume of liquid the glass can hold we need to calculate the volume of each of these and sum them.
Vcilinder = pi*r²*h = 3.14*5²*3 = 235.5 in³
Vhalfsphere = (2*pi*r³)/3 = (2*3.14*5³)/3 = 261.67 in³
Vcup = Vcilinder + Vhalfsphere = 235.5 + 261.67 = 497.17 in³
The cup can hold 497.17 in³ of liquid.
