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3 years ago

Consider the following JavaScript program:

Computers and Technology

1 answer:

dem82 [27]3 years ago

7 0

Answer:

Variable Where Declared

In Sub1 :

A Sub1

Y Sub1

Z Sub1

X Main

In Sub2:

A Sub2

B Sub2

Z Sub2

Y Sub1

X Main

In Sub3 :

A Sub3

X Sub3

W Sub3

Y Main

Z Main

Explanation:

In static-scoped languages with nested subprograms, the declaration of a variable is checked with the subprogram, if it is not found, it check within the parent method that called it, it continue until it find a declaration, if no declaration is found, it display an error.

In Sub1, a, y, z is declared there while the declaration of x is found in main.

In Sub2, a, b, z is declared, declaration of y is found in sub1 and declaration of x is found in main.

In Sub3, a, x, w is declared while the declaration of y, z is from the main.

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2 years ago

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1 year ago

When writing test methods, what functionality is verified by the system method "runAs()"?

olchik [2.2K]

Answer:

The main functionality verified by this test method command is user sharing record.

Explanation:

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If there is no or expired your personal or organization license you can just make a new user with this runAS() command.

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3 years ago

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pychu [463]

Answer:

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3 years ago

Meg[] elements = {new Lois(), new Stewie(), new Meg(), new Brian()}; for (int i =0; i

Stells [14]

Complete question is attached as snapshot.

Answer:

This will result in a compilation error.

Here's the inheritance hierarchy:

Meg -> Lois -> Brian -> Stewie

Now Meg has 2 public Fxns, a() and toString().

Lois inherits from Meg and all its public functions as well but, overrides the a() fxn of its super class.

So finally Lois has fxns a(), b() and toString().

Brian extends Lois and inherits all the above listed fxns of Lois, but overrides the b() and toString() fxns.

Stewie extends Brian and inherits all the fxns of Brian, but overrides the a() and toString() fxns.

In the Main driver fxn, we call a() and b() methods of all these classes but, the base class Meg has no b() and it is not extending any class so its not available in its scope.

This results in a compilation error.

Explanation:

7 0

3 years ago