Let x be the smaller integer, then x+2 is the larger integer. We're given x^2+(x+2)^2=164 Expand and simplify 2x^2+4x+4=164 x^2+2x-80=0 (x-8)(x+10)=0 => x=-10 or x=8.
Therefore the integers are{8,10} or {-10,-8}. Note: question asks for integers, so negative integers count.
I believe it would be addition property of equality since you can add 14 and 8 to recieve the number that the 8 is being subtracted from to get 14. So in this case x would equal 22.
