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3 years ago

Select the symbol = (equal to) or ≠ (not equal to) to make the expression true. {0} ? { }

1 answer:

3 0

$\{0\} \not = \{\}$ because $\{0\}$ is a set with the element 0, so it's not the empty set, while $\{\}$ is the empty set.

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Figure A is a scale image of figure B

serious [3.7K]

X=36

Divide the corresponding side (16) by 4/7

5 0

4 years ago

Find the equation of the straight line that passes through the points (1, 10) and (3, 2)

Aloiza [94]

Answer:

y = -4x + 14

Step-by-step explanation:

using the slope intercept form of a line

y = mx + c

Given points

1, 10
3, 2

slope (m) =

$= \frac{y2 - y1}{x2 - x1} \\ = \frac{2 - 10}{3 - 1} \\ = \frac{ - 8}{2} \\ = - 4$

taking one point as for filling x and y and finding the y intercept (c)

y =mx + c

10 = (-4) × 1 + c

10 + 4 = c

14 = c

therefore the equation is

y = -4x + 14

6 0

3 years ago

Read 2 more answers

the equation is -2x² = 4-3 (x + 1) and the question is justify that it is a 2nd degree equation with the unknown x complete.

Serggg [28]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equation

-2x² = 4-3 (x + 1)

-2x² = 4-3x-3

-2x² = -3x -7

0 = 2x² -3x -7

We know that the degree of the equation is the highest power of x variable in the given equation.

In the equation 0 = 2x² -3x -7 the highest power of x variable in the given equation is 2.

Thus, the degree of the equation is 2.

Also in the equation 0 = 2x² -3x -7, the unknown variable is 'x'.

Let us determine the value 'x'

2x² -3x -7 = 0

Add 7 to both sides

$2x^2-3x-7+7=0+7$

$2x^2-3x=7$

Divide both sides by 2

$\frac{2x^2-3x}{2}=\frac{7}{2}$

$x^2-\frac{3x}{2}=\frac{7}{2}$

Add (-3/4)² to both sides

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{7}{2}+\left(-\frac{3}{4}\right)^2$

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{65}{16}$

$\left(x-\frac{3}{4}\right)^2=\frac{65}{16}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{3}{4}=\sqrt{\frac{65}{16}}$

$x-\frac{3}{4}=\frac{\sqrt{65}}{\sqrt{16}}$

$x-\frac{3}{4}=\frac{\sqrt{65}}{4}$

Add 3/4 to both sides

$x-\frac{3}{4}+\frac{3}{4}=\frac{\sqrt{65}}{4}+\frac{3}{4}$

$x=\frac{\sqrt{65}+3}{4}$

similarly solving

$x-\frac{3}{4}=-\sqrt{\frac{65}{16}}$

$x=\frac{-\sqrt{65}+3}{4}$

So the solution of the equation will have the values of x such as:

$x=\frac{\sqrt{65}+3}{4},\:x=\frac{-\sqrt{65}+3}{4}$

6 0

3 years ago

In a candy store a $5.00 jar of candy is on a boat 50% of what is the discount? What is the sale price of the jar of candy?

Effectus [21]

STEP 1:
Discount $= Price times discount %

=$5.00 * 50%
=$5.00 * 0.50
=$2.50 discount amount

STEP 2:
Sale price= Original $ - Discount amount

=$5.00 - $2.50
=$2.50 sale price

ANSWER: Discount amount is $2.50 and the sale price is also $2.50.

Hope this helps! :)

7 0

3 years ago

Refer to Table 24-1. If Year 1 is the base year, then the inflation rate in Year 2 was

9966 [12]

Answer:

Step-by-step explanation:

7 0

2 years ago