If I had a term mark of 77% and an exam mark of 70 what is my final mark
1 answer:
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The picture in the attached figure
we know that
volume of the regular pyramid=(1/3)*area of the base*height
area of the base=12*12-----> 144 units²
height=71 units
substitute
volume of the regular pyramid=(1/3)*144*71-----> 3408 units³
the answer is
3408 units³
we know that
volume of the regular pyramid=(1/3)*area of the base*height
area of the base=12*12-----> 144 units²
height=71 units
substitute
volume of the regular pyramid=(1/3)*144*71-----> 3408 units³
the answer is
3408 units³