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soldi70 [24.7K]
3 years ago
5

As sum of money double in 20 years on simple interest . It will triple at the same rate in

Mathematics
1 answer:
11111nata11111 [884]3 years ago
5 0
40 years and as rate is 5%
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The reference angle for an angle whose measure is 260° is _____. 60° 80° 100°
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The answer to the question is <span> 80°</span>
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the expression 12g gives the number of kilograms a car can travel using g liters of gasoline. how far can this car travel on 5 1
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It's the product of 12 and 5 1/2, so the answer is 66.
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Choose the slope _intercept form of 3x+2y=5
sukhopar [10]

Answer:

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2y=5-3x

y=5/2-3/2x

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y=2.5-1.5x

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At a certain time of the day, a tree that is x meters tall casts a shadow that is x-49 meters long. If the distance from the top
nikklg [1K]

The height of the tree is 60 meters.

Explanation:

Let the height of the tree be x. The tree casts a shadow of x-49 meters and the distance from the top of the tree to the end of the shadow is x+1 meters.

The sides of the triangle are attached in the image below:

Using pythagoras theorem,

x^{2}+(x-49)^{2}=(x+1)^{2}

Expanding, we get,

2 x^{2}-98 x+2401=x^{2}+2 x+1

2 x^{2}-98 x+2400=x^{2}+2 x

2 x^{2}-100 x+2400=x^{2}

x^{2}-100 x+2400=0

Solving the equation using the quadratic formula x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}, we get,

x=\frac{-(-100)\pm\sqrt{(-100)^{2}-4 \cdot 1 \cdot 2400}}{2 \cdot 1}

Simplifying, we have,

x=\frac{100\pm\sqrt{10000-9600}}{2}

x=\frac{100\pm\sqrt{400}}{2}

x=\frac{100\pm{20}}{2}

Thus,

x=\frac{100+20}{2} \\x=\frac{120}{2} \\x=60  and  x=\frac{100-20}{2} \\x=\frac{80}{2} \\x=40

where the value x=40 is not possible because substituting the value x=40 in x-49 results in negative solution. Which is not possible.

Hence, the value of x is 60.

Thus, The height of the tree is 60 meters.

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2 years ago
Amber is solving the inequality |x+6|-12&lt;13 by graphing. Which equations should Amber graph?
DENIUS [597]

Answer:

  • y₁ = |x + 6| and y₂ = 25

Step-by-step explanation:

<u>Given inequality</u>

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To solve this inequality graphically you need two graphs according left and right sides of inequality

<u>So the graphs should be:</u>

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See attached for the graph

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