Answer: Option (3) is the correct answer.
Explanation:
It is known that general chemical formula of an amine is . Where R is any alkyl group and
represents the amine group.
On the other hand, an aldehyde group is represented by CHO and general formula R-CHO. So, there is no nitrogen atom present in an aldehyde group.
An alcohol group is represented by -OH and general formula R-OH. There is also no nitrogen atom present in an alcohol.
An ether group is represented by -O and general formula R-O-R' where R and R' might be same or different alkyl groups. Hence, there is also no nitrogen atom present in an ether.
Thus, we can conclude that out of the given options amine is the class of organic compounds which contains nitrogen.
Answer:
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number of particles.
To calculate the number of moles, we use the equation:
1 mole of zinc weighs = 65.38 g
moles of Zinc weigh =
Thus mass of one atom of Zinc weigh
In a 0.20 M solution, a weak acid is 3.0% dissociated, the value of
H₃O⁺ =9.19 × 10⁻² OH⁻ = 1.09 × 10⁻¹³, pH =1.04 , pOH = 12.96
<h3>What is pH?</h3>The term pH, which originally stood for "potential of hydrogen" (or "power of hydrogen"), is used in chemistry to describe how acidic or basic an aqueous solution is. Lower pH values are summarized for acidic solutions (solutions with higher H+ ion concentrations) than for basic or alkaline solutions.
The pH scale is inversely indicates to the concentration of hydrogen ions in the solution and is logarithmic.
⇒pH = -log()
Acidic solutions are those with a pH below 7, and basic solutions are those with a pH above 7, at a temperature of 25 °C (77 °F). At this temperature, solutions with a pH of 7 are neutral (e.g. pure water). The pH neutrality relies on temperature, falling below 7 if the temperature rises above 25 °C.
Lets find [H₃O⁺]
Because 12.5% of the weak acid dissociated, 12.5% of the concentration of the weak acid also produced H3O.
H₃O = HA × 0.125
= 0.735 M × 0.125
= 9.19 × 10⁻²
Lets find [OH⁻]
Using the Kw = 1.0 × 10⁻¹⁴
Kw = [H₃O⁺][OH⁻]
[OH⁻] = Kw / [H₃O⁺]
= 1.0 × 10⁻¹⁴ / 9.19 × 10⁻²
= 1.09 × 10⁻¹³
Lets find pH
pH = -log[H₃O⁺]
= -log(9.19 × 10⁻²)
= 1.04
Lets find pOH
Using pH +pOH = 14
pH +pOH = 14
pOH = 14 - pH
= 14 - 1.04
= 12.96
Learn more about pH
#SPJ4