A steel block has a volume of 0.08 m³ and a density of 7,840 kg/m³. What is the force of gravity acting on the block (the weight
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Answer:
Equilibrium concentrations of the gases are
Explanation:
We are given that for the equilibrium
Temperature,
Initial concentration of
We have to find the equilibrium concentration of gases.
After certain time
2x number of moles of reactant reduced and form product
Concentration of
At equilibrium
Equilibrium constant
Substitute the values
By solving we get
Now, equilibrium concentration of gases
156251.099 grams of O₂ are required to burn 17.0 gal of C₈H₁₈
<h3>Further explanation</h3>Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of mass
The unit of density can be expressed in g / cm³ or kg / m³
Density formula:
ρ = density
m = mass
v = volume
1 gal equal to = 3785.41 ml
then 17.0 gal = 17 x 3785.41 = 64351.97 ml Octane
grams Octane = ρ x ml
grams Octane = 0.692 g.ml x 64351.97
grams Octane = 44531.563
molar mass Octane (C₈H₁₈) = 114
mole Octane = grams : molar mass
mole Octane = 44531.563 : 114
mole Octane = 390.627
From the reaction
C₈H₁₈ + 25/2 O₂ ⇒ 8 CO₂ + 9H₂O
mole C₈H₁₈ : mole O₂ = 1 : 25/2
mole O₂ = 4882.846
grams O₂ = mole x molar mass
grams O₂ = 4882.846 x 32
grams O₂ = 156251.099
<h3>Learn more </h3>moles of water
grams of oxygen required
mass of copper required
Keywords: Octane, mole, mass, gal, density
