Question

In a 0.735 M solution, a weak acid is 12.5% dissociated.(a) Calculate the H₃O⁺, pH, OH⁻, and pOH of the solution.

Answer 1

In a 0.20 M solution, a weak acid is 3.0% dissociated, the value of

H₃O⁺ =9.19 × 10⁻² OH⁻ = 1.09 × 10⁻¹³, pH =1.04 , pOH = 12.96

What is pH?

The term pH, which originally stood for "potential of hydrogen" (or "power of hydrogen"), is used in chemistry to describe how acidic or basic an aqueous solution is. Lower pH values are summarized for acidic solutions (solutions with higher H+ ion concentrations) than for basic or alkaline solutions.

The pH scale is inversely indicates to the concentration of hydrogen ions in the solution and is logarithmic.

⇒pH = -log($a_{H+}$)

Acidic solutions are those with a pH below 7, and basic solutions are those with a pH above 7, at a temperature of 25 °C (77 °F). At this temperature, solutions with a pH of 7 are neutral (e.g. pure water). The pH neutrality relies on temperature, falling below 7 if the temperature rises above 25 °C.

Lets find [H₃O⁺]

Because 12.5% of the weak acid dissociated, 12.5% of the concentration of the weak acid also produced H3O.

H₃O = HA × 0.125

      = 0.735 M × 0.125

      = 9.19 × 10⁻²

Lets find [OH⁻]

Using the Kw = 1.0 × 10⁻¹⁴

Kw = [H₃O⁺][OH⁻]

[OH⁻] = Kw / [H₃O⁺]

         = 1.0 × 10⁻¹⁴ / 9.19 × 10⁻²

         = 1.09 × 10⁻¹³

Lets find pH

pH = -log[H₃O⁺]

     = -log(9.19 × 10⁻²)

     = 1.04

Lets find pOH

Using pH +pOH = 14

pH +pOH = 14

pOH = 14 - pH

        =  14 - 1.04

        = 12.96

Learn more about pH

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