Question

Calculate the mass of one atom of zinc in grams. (Hint: g/particle)

Answer 1

Answer: $10.17\times 10^{-23}g$

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given atoms}}{\text{Avogadro's number}}=\frac{1}{6.023\times 10^{23}}=0.16\times 10^{-23}atoms$

1 mole of zinc weighs = 65.38 g

$0.16\times 10^{-23}$  moles of Zinc weigh = $\frac{63.58}{1}\times 0.16\times 10^{-23}=10.17\times 10^{-23}g$

Thus mass of one atom of Zinc weigh $10.17\times 10^{-23}g$