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3 years ago

Given g(x) is a linear function and passes through the points (3,2) and (5,-1),

Mathematics

1 answer:

Slav-nsk [51]3 years ago

7 0

Answer:

-3/2

Step-by-step explanation:

here it goes. (-1)- (2) / (5)-(3)

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0.1 x 23<br><br><br><br><br><br><br><br> Please help me

zhannawk [14.2K]

Answer:

the answer would be 2.3

4 0

3 years ago

Read 2 more answers

Pls help this is for math ill give a brainly

olasank [31]

Answer: The last one - 5 1/3 divided by 1/6

Step-by-step explanation:

since you are trying to figure out how much she runs a day, u divide

Hope this helps :)

6 0

3 years ago

A regular octagon has a radius of 6 ft and a side length of

Svetlanka [38]

Answer:

<h2>Area of the regular octagon is approximately 102ft²</h2>

Step-by-step explanation:

Given the radius and length of a side of regular octagon as shown;

radius = 6ft and length of side = 4.6ft

Area of a regular octagon is expressed as $A = 2(1+\sqrt{2} )a^{2}$ where a is the length of one side. Given a = 4.6ft

Area = $A = 2(1+\sqrt{2} )(4.6)^{2}\\$

$= 2(1+\sqrt{2} )*21.16\\= (2+2\sqrt{2})*21.16\\ = 4.83*21.16\\= 102.20ft^{2} \\$

Area of the regular octagon is approximately 102ft²

3 0

3 years ago

Find the point on the plane 4x+3y+z=10 that is nearest to (2,0,1). What are the values of x, y, and z for the point? x= 28 /

MariettaO [177]

Answer:

$\frac{1}{\sqrt{26}}$ .

Step-by-step explanation:

The minimun distance between a point and a plane is the perpendicular distance. The formula is

d = $\frac{|Ax_0+By_0+Cz_0+D|}{\sqrt{A^{2}+B^{2}+C^{2}}}$

where $(x_0,y_0,z_0)=(2,0,1)$ , A=4, B=3, C=1 and D=-10. So, the distance is

d = $\frac{|8+1-10|}{\sqrt{16+9+1}}$

d = $\frac{|-1|}{\sqrt{26}}$

d = $\frac{1}{\sqrt{26}}$ .

4 0

3 years ago

( 2 x - 3 ) ( 7 x + 4)

weeeeeb [17]

Answer:5x times -7

Step-by-step explanation:

You ignore the brackets and move the 2x to the other side. Then move the 4 to the other side

3 0

3 years ago