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kakasveta [241]
3 years ago
8

Given g(x) is a linear function and passes through the points (3,2) and (5,-1),

Mathematics
1 answer:
Slav-nsk [51]3 years ago
7 0

Answer:

-3/2

Step-by-step explanation:

here it goes. (-1)- (2) / (5)-(3)

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Which represents a unit rate? The cost of cat food is $36 per 3 bags
coldgirl [10]

Step-by-step explanation:

To find unit rate

1 bag = 36÷ 3 = 12

So unit rate = $12

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3 years ago
What quadrant is (0,-7) found in?
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3 years ago
how to find the area of each face of an equilateral triangular prism that has a surface area of 500 square units
KATRIN_1 [288]

Answer:Break that up

Step-by-step explanation:See how you can break up 500 to make it easier for yourself

7 0
3 years ago
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Discuss the continuity of the function on the closed interval.Function Intervalf(x) = 9 − x, x ≤ 09 + 12x, x &gt; 0 [−4, 5]The f
quester [9]

Answer:

It is continuous since \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)

Step-by-step explanation:

We are given that the function is defined as follows f(x) = 9-x, x\leq 0 and f(x) = 9+12x, x>0 and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity)  x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all \mathbb{R}. So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that

\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x) (this is the definition of continuity at x=0)

Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that

\lim_{x\to 0^{-}} f(x) = \lim_{x\to 0^{-}} 9-x = 9. This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.

Note that when x>0, we have that f(x) = 9+12x. In this case, we have that

\lim_{x\to 0^{+}} f(x) = \lim_{x\to 0^{+}} 9+12x = 9. As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.

Thus, \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)=9, so by definition, f is continuous at x=0, hence continuous over the interval [-4,5].

5 0
3 years ago
Read 2 more answers
What is the EXACT volume of this composite figure?
mariarad [96]

Answer:

324π in.³

Step-by-step explanation:

The figure is a cone and a half sphere.

V = (1/3)πr²h + [(4/3)πr³]/2

V = (1/3)π(36 in.²)(15 in.) + (2/3)π(216 in.³)

V = [180π + 144π] in.³

V = 324π in.³

5 0
2 years ago
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