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julsineya [31]
3 years ago
13

The diameter of a circle is 8 inches. What is the area?

Mathematics
2 answers:
zimovet [89]3 years ago
8 0
16 pi inches squared brotha
elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

1 6   p i   s q u a r e s   i s    m y    f i n a l    a n s w e r ! ! !   y o u r   w e l c o m e

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Read 2 more answers
Pre-Calculus - Systems of Equations with 3 Variables please show work/steps
inessss [21]

Answer:

x = 10 , y = -7 , z = 1

Step-by-step explanation:

Solve the following system:

{x - 3 z = 7 | (equation 1)

2 x + y - 2 z = 11 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Swap equation 1 with equation 2:

{2 x + y - 2 z = 11 | (equation 1)

x + 0 y - 3 z = 7 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y/2 - 2 z = 3/2 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Multiply equation 2 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

-x - 2 y + 9 z = 13 | (equation 3)

Add 1/2 × (equation 1) to equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - (3 y)/2 + 8 z = 37/2 | (equation 3)

Multiply equation 3 by 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - y - 4 z = 3 | (equation 2)

0 x - 3 y + 16 z = 37 | (equation 3)

Swap equation 2 with equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x - y - 4 z = 3 | (equation 3)

Subtract 1/3 × (equation 2) from equation 3:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y - (28 z)/3 = (-28)/3 | (equation 3)

Multiply equation 3 by -3/28:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y + 16 z = 37 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 16 × (equation 3) from equation 2:

{2 x + y - 2 z = 11 | (equation 1)

0 x - 3 y+0 z = 21 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 2 by -3:

{2 x + y - 2 z = 11 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{2 x + 0 y - 2 z = 18 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Add 2 × (equation 3) to equation 1:

{2 x+0 y+0 z = 20 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by 2:

{x+0 y+0 z = 10 | (equation 1)

0 x+y+0 z = -7 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer: {x = 10 , y = -7 , z = 1

3 0
3 years ago
What is the range of the graphed function?
s2008m [1.1K]

Answer:

{y| y is a real number}

Step-by-step explanation:

The range is all the y's that an equation can produce or all the y's on a graph of the function.

This graph has every and any real y (because it keeps going forever, even off the screen or paper) It's a little hard to see, bc we just see it going left and right mostly, but it is also slightly going up (to the left) and down (to the right)

5 0
2 years ago
Please can someone help me
vazorg [7]

Answer:

A, C ,E

Step-by-step explanation:

3 0
3 years ago
1. ∠XVR =
Lelechka [254]

Answer/Step-by-step explanation:

1. ∠XVR = 180 - <XVW (angle on a straight line)

∠XVR = 180 - 55°

∠XVR = 125°

2. ∠RVS = <XVW (Vertical angles are congruent)

∠RVS = 55°

3. ∠WVS = ∠XVR (vertical angles are congruent)

∠WVS = 125°

4. ∠RST = <R + <RVS (exterior angle theorem)

<RST = 55 + 55

<RST = 110°

5. ∠RSV = 180 - (<R + <RVS) (sum of triangle)

∠RSV = 180 - (55 + 55)

∠RSV = 70°

6. ∠VSU = <RST (vertical angles are congruent)

<VSU = 70°

7. ∠UST = <RSV (vertical angles)

<UST = 70°

8. ∠TUS = 180 - (<UST + <T) (sum of triangle)

<TUS = 180 - (70 + 71)

<TUS = 39°

6 0
3 years ago
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