Let us formulate the independent equation that represents the problem. We let x be the cost for adult tickets and y be the cost for children tickets. All of the sales should equal to $20. Since each adult costs $4 and each child costs $2, the equation should be
4x + 2y = 20
There are two unknown but only one independent equation. We cannot solve an exact solution for this. One way to solve this is to state all the possibilities. Let's start by assigning values of x. The least value of x possible is 0. This is when no adults but only children bought the tickets.
When x=0,
4(0) + 2y = 20
y = 10
When x=1,
4(1) + 2y = 20
y = 8
When x=2,
4(2) + 2y = 20
y = 6
When x=3,
4(3) + 2y= 20
y = 4
When x = 4,
4(4) + 2y = 20
y = 2
When x = 5,
4(5) + 2y = 20
y = 0
When x = 6,
4(6) + 2y = 20
y = -2
A negative value for y is impossible. Therefore, the list of possible combination ends at x =5. To summarize, the combinations of adults and children tickets sold is tabulated below:
Number of adult tickets Number of children tickets
0 10
1 8
2 6
3 4
4 2
5 0
Answer:
it took her 35 minutes to finish
The least common multiple should be 36 because it is the smallest number 4 and 9 go into.
Idfk broooo I need help with this too
Hello there, and thank you for asking your question here on brainly.
<em><u>Short answer: B. 0.71
</u></em>
<em>Why?
</em>
To find probability, you have to divide both the total number of possibilities, (7) and divide that by the greatest number of possibilities. (5). <em>5/7 </em>≈ <em>0.71
Hope this helped you! ♥</em>
