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3 years ago

Megan creates a scale drawing of a car. The ratio of her scale drawing length to actual car

Mathematics

2 answers:

beks73 [17]3 years ago

8 0

Answer: The length of the car in Ivan's scale drawing is 8 cm.

Step-by-step explanation: Megan creates a scale drawing for a car and her scale is measured as 3 cm : 2 m. One meter equals one hundred centimetres, that means the 3 centimetres used in Megan's drawing equals two hundred centimetres in actual length of the car. Hence, for every two centimetres she draws, the actual length is times three hundred, which can be represented as follows;

Ratio = 3 : 200

If the drawing was eventually six centimetres, then the actual car length would be,

3/200 = 6/x

Where x represents the actual length of the car

3x = 6*200

x = (6*200)/3

x = 400

Therefore the actual length of the car is 400 centimetres (or 4 metres)

Ivan draws the same car using a ratio of two centimetres to one metre. With our conversion rate already given above (100 cm = 1 m), Ivan's ratio is

2 : 100

Having known the length of the actual car to be 400 centimetres, Ivan's drawing would have a scale calculated as;

2/100 = y/400

Where y represents the length of the car in Ivan's scale drawing

2*400 = 100y

(2*400)/100 = y

8 = y

Therefore the length of the car in Ivan's scale drawing is 8 centimetres

Alika [10]3 years ago

6 0

Answer:

Givens

The length of the car in her drawing is 6 cm.
The scale is 3 cm : 2 m.
Ivan draws with a relation 2 cm : 1 m.

First, we need to find the actual length of the car using Megan's ratio.

If 2 centimeters is equivalent to 1 actual meter of the car, 6 centimeters of drawing would be equal to

$M=6cm \times \frac{2m}{3cm} =4m$

Therefore, the car is 4 meters long.

Now, using this information, we can find the length of the scale drawing of Ivan.

$I=4m \times \frac{2cm}{1m}=8cm$

Therefore, Ivan's drawing is 8 centimeters long.

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Step-by-step explanation:

Let A be the event that the test result is positive and B the event that the athlete uses Steroids. We are given the following

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$P(B^c|A^c) = \frac{P(A^c|B^c)P(B^c)}{P(A^c)}= \frac{P(A^c|B^c)P(B^c)}{1-P(A)}= \frac{(1-P(A|B^c))P(B^c)}{1-P(A)}=\frac{98\%\cdot 95\%}{1-6.4\%}= 99.47\%$

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