The answer is C
call the length is a => the diagonal is a+1
11^2 + a^2=(a+1)^2
<=> 121 + a^2=a^2 + 2a +1
<=>120=2a
<=> a=60
The answer to this question is 30
It would be at 35 when you work all then problems together
(100)= 0.25*100=15 times.
<span>SO, the train will be late 15 times in 100 days.
Hope i helped:P </span>
