All categories

2 years ago

75 is 128% of what number

Mathematics

2 answers:

rosijanka [135]2 years ago

7 0

Answer: 58.59

Step-by-step explanation:

Trust me it is correct!

Oksana_A [137]2 years ago

5 0

$\bold \pink{let \: the \: number \: be \: x}$

$\mathsf{128\% \times x = 75}$

$\\ \\ \frac{128}{100} \times x = 75 \\ \\ x = \frac{75}{1} \times \frac{100}{128} \\ \\ x = \frac{7500}{128}$

$\boxed{x = 58.59375}$

75 is 128% of 58.59375

You might be interested in

Identify the exponential function for the given graph.

Korolek [52]

Answer:

Step-by-step explanation:

C - 3(2^x).

8 0

3 years ago

, find a1 and d. 34, 40, 46, 52, 58, 64

yulyashka [42]

Answer:

a1 = 34, d = 6.

Step-by-step explanation:

a1 = the first term = 34.

To find d subtract: 2nd term - first term , third term - second term and so on.

d = 40 - 34 = 6.

Also 46-40 = 6

WE get the same value 6 for the other given terms.

6 is added to each term to get the next term

5 0

3 years ago

The mass of the sun is 2.13525×1030 kilograms. The mass of Mercury is 3.285×1023 kilograms. How many times greater is the mass o

Helga [31]

<span>6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.</span>

8 0

3 years ago

Read 2 more answers

How would I do this?

Georgia [21]

Work shown above! Answer would be 110 degrees!

3 0

3 years ago

Analyze the diagram below and complete the instructions that follow.

lora16 [44]

Answer:

$\displaystyle y=2\sqrt{6}$

$\displaystyle x=2\sqrt{2}$

Step-by-step explanation:

<u>Trigonometric Ratios </u>

The ratios of the sides of a right triangle are called trigonometric ratios.

The longest side of the right triangle is called the hypotenuse and the other two sides are the legs.

Selecting any of the acute angles as a reference, it has an adjacent side and an opposite side. The trigonometric ratios are defined upon those sides.

The image provided shows a right triangle whose hypotenuse is given. We are required to find the value of both legs.

Let's pick the angle of 30°. Its adjacent side is y. We can use the cosine ration, which is defined as follows:

$\displaystyle \cos 30^\circ=\frac{\text{adjacent leg}}{\text{hypotenuse}}$