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3 years ago

(3x+20) (5x-16) find the value of x

Mathematics

2 answers:

eduard3 years ago

5 0

The Value Of X Is 15x^2+52x−320

raketka [301]3 years ago

4 0

Answer:

$15x^{2}+52x-320$

Step-by-step explanation:

You can only evaluate the terms, but you can not find the value of X since it is not an equation, or it is not equalized to something, in this case you only have to do the multyplication of both binomials, and it would be like this:

(3x+20)(5x-16)

This would be

$15x^{2}-48x+100x-320$

After adding similar terms you get:

$15x^{2}+52x-320$

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4 years ago

O. Find the distance between P (10,-7) and Q (7,- 10). Leave your answer in radical form.

mr Goodwill [35]

Answer:

$\sqrt{18}$ or $3\sqrt{2}$ units.

Step-by-step explanation:

To find the distance between two points, we can use the Distance Formula.

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given:

P (10, -7) ⇒ x₁ = 10, y₁ = -7

Q (7, -10) ⇒ x₂ = 7, y₂ = -10

Substitute the given values into the formula and simplify.

$\\\implies d=\sqrt{\bold{(7-10)}^2+\bold{(-10-(-7))}^2}\\\\\implies d=\sqrt{\bold{(-3)}^2+\bold{(-10+7)}^2}\\\\\implies d=\sqrt{9+\bold{(-3)}^2}\\\\\implies d=\sqrt{\bold{9+9}}\\\\\implies d=\sqrt{\bold{18}}\\\\\implies d=\sqrt{\bold{9}\times2}\\\\\implies d=3\sqrt{2}$

The distance between points P and Q is $\sqrt{18}$ or $3\sqrt{2}$ units.

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brainly.com/question/27991769

brainly.com/question/21095661

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