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nataly862011 [7]

3 years ago

10

A taxi in myrtle beach charges $2 per mile and $1 per person. If a taxi cab ride for 2 people cost $12, how far did the taxi cab

travel ( don’t include units (miles) in the answer)

1 answer:

GarryVolchara [31]3 years ago

4 0

Answer:

I belive the answer is 5

Step-by-step explanation:

$12- $2 for ppl= $10

$10÷$2 per mile = 5

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Right answers, marking brainliest if correct.

GrogVix [38]

Answer:

1) 1) 97 – 39. It becomes

100 - 40 = 60

2)2) 812,344 – 187,675. It becomes

800000 - 200000 = 600000

3)321 + 79. It becomes

300 + 80 = 410

4) 315 x 821. It becomes

300 + 800 = 1100

5) 562 x 791. It becomes

600× 800 = 480000

6) 82 x 156. It becomes

80×200 = 16000

7) 711 x 884. It becomes

700×900 = 630000

8) 126 x 952. It becomes

100×1000 = 100000

9) 824 x 541. It becomes

800× 500 = 400000

10) 4027 x 78. It becomes

4000×80 = 320000

11) 796 x 123. It becomes

800×100 = 80000

12) 817 19. It becomes

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13) 3615 72. It becomes

4000/70 = 57.1 = 60

14) 232 64. It becomes

200/60 = 33.3 = 30

15) 559 81. It becomes

600/80 = 7.5 = 8

16) 2986 222. It becomes

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17) 10275 232. It becomes

10000/200 = 50

18) 7428 286. It becomes

7000/300 = 23.3 = 20

19) 7143 369. It becomes

7000/400 = 17.5 = 18

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Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Jaden is flying a kite and let’s off 275 feet of string. If the kite is 150 feet above ground and assuming the string is straigh

vivado [14]

Answer:

≈ 33°

Step-by-step explanation:

So, first, you can draw a visual. Refer to the image attached below:

Using this info, you can use trigonometric ratios. Recall that:

tangent = opposite side/adjacent side

sine = opposite side/ hypotenuse

cosine = adjacent side/hypotenuse

You can clearly see that you have an opposite side and a given hypotenuse. This means we'll be using sine.

So:

$sinX = \frac{150}{275}$

However, we're not trying to find sinX, we're trying to find X.

So we would have to use inverse sine, which would then be:

$X = sin-1 (\frac{150}{275} )$

Put this into your calculator, and:

X ≈ 33.05573115...

3 0

3 years ago

The diagram below shows the dimensions of a triangular park built in a new housing development. Two side lengths and one angle m

evablogger [386]

ANSWER

$x = 50.5 \degree$

EXPLANATION

We use the sine rule for solving triangles.

This is given by the formula,

$\frac{ \sin(A) }{a} = \frac{ \sin(B) }{b} = \frac{ \sin(C) }{c}$

From the triangle,

$\frac{ \sin(x) }{60} = \frac{ \sin(40) }{50}$

We multiply both sides of the equation by 60 to get,

$sin(x) = \frac{ 60\sin(40 \degree) }{50}$

$sin(x) = 0.7713$

We solve for x to obtain,

$x = arcsin(0.7713)$

$x = 50.475$

To the nearest tenth, we round to one decimal place to get,

$x = 50.5 \degree$

7 0

3 years ago

What is 2 dollars to 40 cents as a fraction in lowest terms?

pav-90 [236]

It is 5/1
200/40
20/4
5/1

3 0

3 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

so

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

so

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago