Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
2 by 7 + – is equals to 1 so we can say that x.
x=1-2/7
x=7/7-2/7
x=5/7
Answer:
<h3>
m∠2 = 67°</h3>
Step-by-step explanation:
m║n ⇒ (9x + 2)° = 74° {Corresponding Angles}
(9x)° = 72°
x = 8
Angles: angle corresponding to angle (5x-1)°, angle 74° and angle 2 add to 180° (straight angle)
(5×8 - 1)° + 74° + m∠2 = 180°
39° + 74° + m∠2 = 180°
113° + m∠2 = 180°
m∠2 = 180° - 113°
m∠2 = 67°
Using elimination method to find y
3x - 4y = -15 (multiply 4)
4x + 3y = 5 (multiply 3)
------------------------------------
12x - 16y = -60
12x + 9y = 15
--------------------- - (substract)
-25y = -75
y = 3
Using subtitution method to find x
3x - 4y = -15
3x - 4(3) = -15
3x - 12 = -15
3x = -3
x = -1
The solution (-1,3)
The answer is C it will be congruent to another angle
