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Bess [88]
3 years ago
6

The solution set, all real numbers greater than or equal to one, proves which of the following inequality statements to be true?

-5x ≥ 6x - 11 -5x ≤ 6x - 11 5x ≤ 6x + 11 -5x ≤ 6x + 11
Mathematics
1 answer:
Juliette [100K]3 years ago
8 0

Answer:

-5x ≤ 6x - 11

Step-by-step explanation:

Solving inequalities involves the same steps as equations with the exception that when multiplying or dividing by a negative coefficient of the variable, the inequality sign will flip.  The solution to one of the inequalities given must be x ≥ 1.  Given this answer, you can solve each to find the matching inequality:

-5x ≥ 6x - 11 or -11x ≥ -11 or x ≤ 1 (flip the sign due to negative coefficient)

-5x ≤ 6x - 11 or -11x ≤ -11 or x ≥ 1 (flip the sign)

5x ≤ 6x + 11 or -x ≤ 11 or x ≥ -1

-5x ≤ 6x + 11 or -11x ≤ 11 or x ≥ -1

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