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Bess [88]
3 years ago
6

The solution set, all real numbers greater than or equal to one, proves which of the following inequality statements to be true?

-5x ≥ 6x - 11 -5x ≤ 6x - 11 5x ≤ 6x + 11 -5x ≤ 6x + 11
Mathematics
1 answer:
Juliette [100K]3 years ago
8 0

Answer:

-5x ≤ 6x - 11

Step-by-step explanation:

Solving inequalities involves the same steps as equations with the exception that when multiplying or dividing by a negative coefficient of the variable, the inequality sign will flip.  The solution to one of the inequalities given must be x ≥ 1.  Given this answer, you can solve each to find the matching inequality:

-5x ≥ 6x - 11 or -11x ≥ -11 or x ≤ 1 (flip the sign due to negative coefficient)

-5x ≤ 6x - 11 or -11x ≤ -11 or x ≥ 1 (flip the sign)

5x ≤ 6x + 11 or -x ≤ 11 or x ≥ -1

-5x ≤ 6x + 11 or -11x ≤ 11 or x ≥ -1

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If f(x)= x-3/x and g(x)= 5x-3, what is the domain of (f•g)(x)
ad-work [718]

f(x)=\dfrac{x-3}{x},\ D_f:x\neq0\\\\g(x)=5x-3,\ D_g=\mathbb{R}\\\\(f\cdot g)(x)=f(x)\cdot g(x)\\\\(f\cdot g)(x)=\dfrac{x-3}{x}\cdot(5x-3)=\dfrac{(x-3)(5x-3)}{x}\\\\D_{(f\cdot g)}=D_f

Answer: The domain of (f•g)(x) is all real numbers except for 0

D=\mathbb{R}-\{0\}

4 0
3 years ago
What is the antiderivative of 3x/((x-1)^2)
ValentinkaMS [17]

Answer:

3 ln(x − 1) − 3/(x − 1) + C

Step-by-step explanation:

∫ 3x / (x − 1)² dx

3 ∫ x / (x − 1)² dx

If u = x − 1, then x = u + 1, and du = dx.

3 ∫ (u + 1) / u² du

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3 ln u − 3/u + C

Substitute back:

3 ln(x − 1) − 3/(x − 1) + C

6 0
3 years ago
What is 2/2 -+7 need friends anyone
kow [346]

Answer:

-6

Step-by-step explanation:

2/2=1

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8 0
2 years ago
Solve the inequality: 12p + 7 > 139
8_murik_8 [283]
If you would like to solve the inequality 12 * p + 7 > 139, you can do this using the following steps:

12 * p + 7 > 139
12 * p > 139 - 7
12 * p > 132       /12
p > 132/12
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The correct result would be p > 11.
4 0
3 years ago
Read 2 more answers
Blanks ?? Help me ??
jenyasd209 [6]
C is 6 because the absolute value of -19 -13 would be 19-13 which equals 6
5 0
3 years ago
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