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Step2247 [10]
3 years ago
14

Which expression is equivalent to the following expression? 2(x + 7)

Mathematics
2 answers:
Lerok [7]3 years ago
6 0

Answer:

I believe the answer is (C) 2x+14.

You have to distribute the 2 and multiply it to the x and the 14.

Step-by-step explanation:

Multiply the x by the 2 to get 2x

multiply the 7 by the 2 to get 14

so the equation is: 2x + 14

I hope this is correct.

Kipish [7]3 years ago
4 0

Answer:

C

Step-by-step explanation:

Use distributive property. distribute the 2 into both numbers by multiplying them both by 2 and you get 2x + 14

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90 to the nearest tenth
melamori03 [73]

Answer:

90

Step-by-step explanation:

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7 0
2 years ago
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The period 7 (in seconds) of a pendulum is given by T = 2pi√( L divided by 32) where L stands for the length (in feet) of the pe
oksano4ka [1.4K]

Answer:

128 feet

Step-by-step explanation:

t = 2\pi \sqrt{\frac{l}{32} }

So now we will substitute the values of T and π into the equation.

12.56 = 2 \times 3.14 \sqrt{ \frac{l}{32} }

12.56 = 6.28 \sqrt{ \frac{l}{32} }

Divide both sides by 6.28

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Square both sides.

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5 0
1 year ago
1 -12.166 + (-1.54)​
castortr0y [4]

Answer:

-12.706

Step-by-step explanation:

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Then we subtract: -12.706

8 0
3 years ago
A circular disc has a circumference of 16pi meters. if we multiply the radius of the circular disc is by 10, what is the circumf
Flauer [41]

The circumference of the new disc 160Π that is 10 time of old circumference.

Step-by-step explanation:

Given,

Circumference of circular disc = 16Π (pi = Π)

Let, the radius of the circle be 'r'

Formula

The circumference of a circle with r radius = 2 Π r

According to the problem,

2 Π r = 16Π

or, 2r = 16 ( by eliminating the value of Π from both the side)

or, r = 8

Now, we multiply the radius by 10

so, the new radius is 8 X 10 = 80

Now the circumference = 2 Π X 80

= 160Π

Hence, the new circumference also will be 10 times of the older one.

6 0
3 years ago
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seropon [69]
He will pay 26.1$ for 8 2/3 pounds of chicken.

Hope this helps!!

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3 years ago
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