Answer:
y = 1/3*x -3
Step-by-step explanation:
Method 1:
Grab two random points from the line.
(0,-3) and (3,-2)
Using the Point-Slope Form solve for m.
(-3 - (-2)) = m * (0 - (3))
-1 = m * (-3)
m = 1/3
Turning Point-Slope form into Slope intercept Form.
(y - (-3)) = 1/3 * (x - 0)
y + 3 = 1/3x
y = 1/3 - 3
Method 2:
Look at the y-intercept since y-int becomes our b. b = -3
From the y-int count rise/run as thats our Slope m. m = 1/3
Slope-intecept Form:
y = 1/3*x -3
Answer:
Yes
Step-by-step explanation:
x=10 would not however since it is a vertical line and fails the vertical line test where an x value cannot be repeated more than once.
y=10 would be a horizontal line coming from the point (0,10)
the answer to that question is 6000
Answer:
A) The model exists: f(x) = -3x^2 +4x -4
Step-by-step explanation:
A quadratic model will always exist for 3 given points, provided they are not on a line. In that case, a linear model is appropriate.
Here, the slope between -1 and 0 is positive, and the slope between 0 and 3 is negative. Thus, we know these points are not collinear, and a model must exist.
The model is most easily found using a quadratic regression tool. Such is shown in the attachment. It tells us that ...
f(x) = -3x^2 +4x -4
Answer:
C
Step-by-step explanation:
It is stating that it is 15 less(-15) than the Product of 3 and some number(3n)
