Which is a value of x, when 3x^2 + 4 = 40?
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We are given the following equation and want to find the possible values of x
Subtract both sides by 3x
Now, we have this weird equation. Since -15 is NOT equal 15 and there is no other way we could have solved for x, there is no real solution to the given equation.
In other words, there is no value of x that makes the equation true.
Let me know if you need any clarifications, thanks!
~ Padoru