If a lawn measures 40 and 4/5 ft by 50 and 7/8ft how many square feet of seed will he need?

2 answers:

6 0

So convert to improper fracitons (improper=x/y where x>y and the current one is mixed where it is in t s/f form) so

40 and 4/5=(40 times 5)/5 and 4/5=200/5 and 4/5=204/5

50 and 7/8=(50 times 8)/8 and 7/8=400/8 and 7/8=407/8

area=legnth times width
legnth =407/8
width=204/5
multiply 407/8 and 204/5

407/8 times 204/5=(407 times 204)/(8 times 5)=83028/40=2075.7 square feet

the answer is 2075.7 ft^2 of seed

irga5000 [103]3 years ago

4 0

To solve this just take 40 4/5*50 7/8=2075.7 so there would be about 2075.7 square feet of seed to plant.

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The perimeter of a triangle is 510 feet and the sides are in the ratio of 11:16:24. Find the area of the triangle

Nutka1998 [239]

If the sides are in the ratio of 11:16:24, it means that they are all multiples of a same number x, according to these factors.

So, the shorter side is 11x feet long, the middle one is 16x feet long, and the longest side is 24x feet long.

This means that the perimeter is

$11x+16x+24x = 51x$ feet long. But we know that this is 510 feet, so we have

$51x = 510 \implies x = \cfrac{510}{51} = 10$ .

So, the three sides are 110, 160 and 240 feet long.

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